Math, asked by ayush08052002, 11 months ago

(sin3A + sinA)sinA + (cos3A - cosA)cosA = 0​

Answers

Answered by steeldevildhruva89
6
LHS = (Sin3A+SinA)SinA+(Cos3A-CosA)CosA =(3SinA-4sin 3 A+SinA)SinA+(4Cos 3 A-3CosA-CosA)CosA
=4Sin 2 A(1-Sin 2 A)-4Cos 2 A(1-Cos 2 A)
=4Sin 2 ACos 2 A-4Cos 2 ASin 2 A =0 = RHS
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