(sin³theta+cos³theta/sin theta +cos theta) +sin theta costheta =1
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» (sin³Ø + cos³Ø) / (sinØ + cosØ) = 1
Let, sinØ = s and cosØ = c
» (s³ + c³) / (s + c) = 1
» (s + c) (s² + c² - sc) / (s + c) = 1
» sc = 0
» Ø = nπ or n (π/2), n € N
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