sin³theta upon cos theta plus cos ³theta upon sin theta is equal to 2cot2theta
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Answer:
Solution:
LHS =
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/* we know the algebraic identity:
a³-b³ = (a-b)(a²+ab+b²) */
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After cancellation, we get
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/* We know the Trigonometric identity:
sin²A + cos²A = 1 */
= $1+sin\theta cos\theta$
= RHS
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