Math, asked by neha4848, 15 days ago

sin³x+cos³x/sinx+cosx +sin³x-cos³x/ sinx-cosx

Answers

Answered by nikhil4314
0

I hope you understand that

Attachments:
Answered by pandasoumitra2011
1

Answer:

sin³x+cos³x/sinx+cosx +sin³x-cos³x/

Step-by-step explanation:

sin³x+cos³x/sinx+cosx +sin³x-cos³x/

sin3x−cos3x

=sinxsin2x−cosxcos2x

=sinx(1−cos2x)−cosx(1−sin2x)

=sinx−sinxcos2x−cosx+cosxsin2x

=sinx−cosx+(sinx−cosx)sinxcosx

=(sinx−cosx)(1+sinxcosx)

hope it helps you to please mark me brainliest

1000% correct answer

Similar questions