siN3x/sinx-cos3x/cosx =
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Answer:
sin
3
x
sin
x
−
cos
3
x
cos
x
=
2
TRUE, it is an identity
Step-by-step explanation:
Explanation:
sin
3
x
sin
x
−
cos
3
x
cos
x
=
2
sin
(
2
x
+
x
)
sin
x
−
cos
(
2
x
+
x
)
cos
x
=
2
sin
2
x
⋅
cos
x
+
cos
2
x
⋅
sin
x
sin
x
−
cos
2
x
⋅
cos
x
−
sin
2
x
⋅
sin
x
cos
x
=
2
sin
2
x
⋅
cos
x
sin
x
+
cos
2
x
⋅
sin
x
sin
x
−
cos
2
x
⋅
cos
x
cos
x
+
sin
2
x
⋅
sin
x
cos
x
=
2
sin
2
x
⋅
cos
x
sin
x
+
cos
2
x
⋅
sin
x
sin
x
−
cos
2
x
⋅
cos
x
cos
x
+
sin
2
x
⋅
sin
x
cos
x
=
2
sin
2
x
⋅
cos
x
sin
x
+
cos
2
x
−
cos
2
x
+
sin
2
x
⋅
sin
x
cos
x
=
2
sin
2
x
⋅
cos
x
sin
x
+
sin
2
x
⋅
sin
x
cos
x
=
2
2
⋅
sin
x
⋅
cos
x
⋅
cos
x
sin
x
+
2
⋅
sin
x
⋅
cos
x
⋅
sin
x
cos
x
=
2
2
⋅
sin
x
⋅
cos
x
⋅
cos
x
sin
x
+
2
⋅
sin
x
⋅
cos
x
⋅
sin
x
cos
x
=
2
(
2
⋅
cos
x
⋅
cos
x
)
+
(
2
⋅
sin
x
⋅
sin
x
)
=
2
2
⋅
cos
2
x
+
2
⋅
sin
2
x
=
2
2
⋅
(
cos
2
x
+
sin
2
x
)
=
2
2
⋅
(
1
)
=
2
2
=
2
it is an IDENTITY
God bless....I hope the explanation is useful.
please Mark as brainest
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