Math, asked by seemadevi321gmailcom, 10 months ago

Sin3x -Sinx
__________=cot
$x {?}^{2}$

cosx-cos3x

Answers

Answered by unicorn276

1

Answer:

Step-by-step explanation:

cos4x+cos3x+cos2x

=

(sin4x+sin2x)+sin3x

(cos4x+cos2x)+cos3x

=

2sin3xcosx+sin3x

2cos3xcosx+cos3x

=

sin3x[2cosx+1]

cos3x[2cosx+1]

=cot3x

Answered by rk5848513

0

Answer:

3x-sinx/[x]×(?)^(2)[/x]=cot

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