Question

Sin3x -Sinx
__________=cot
$x {?}^{2}$


cosx-cos3x​

Answer 1

Answer:

Step-by-step explanation:

cos4x+cos3x+cos2x

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=  

(sin4x+sin2x)+sin3x

(cos4x+cos2x)+cos3x

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=  

2sin3xcosx+sin3x

2cos3xcosx+cos3x

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=  

sin3x[2cosx+1]

cos3x[2cosx+1]

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=cot3x

Answer 2

Answer:

3x-sinx/[x]×(?)^(2)[/x]=cot