Math, asked by chaynamittal, 10 months ago

(sin3x+sinx)sinx+(cos3x-cosx)cosx=0​

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Answered by Anonymous
4

Answer:

( sin3x + sinx )sinx + (cos3x - cosx)cosx=0 prove it

Ask for details Follow Report by Abubakkar 06.08.2018

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MarkAsBrainliest

MarkAsBrainliest Genius

Answer :

Now,

(sin3x + sinx) sinx + (cos3x - cosx) cosx

= sin3x sinx + sin²x + cos3x cosx - cos²x

= (cos3x cosx + sin3x sinx) - (cos²x - sin²x)

= cos(3x - x) - cos2x

= cos2x - cos2x

= 0

Hence, proved.

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