(sin4-cos4+1)cosec2=2
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LHS :
- (sin⁴A - cos⁴A + 1)cosec²A
- [ (sin²A+cos²A)(sin²A-cos²A) + 1 ] × cosec²A. ( using a² - b² =(a+b)(a-b) )
- { 1(sin²A - cos²A) + 1} × cosec²A
- { sin²A - cos²A + sin²A + cos²A } cosec²A. (as sin²θ + cos² θ = 1)
- { 2sin²A } cosec²A
- 2 ( as sinA = 1/cosecA)
- = RHS
Hence proved ..
#answerwithquality
#BAL
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