sin40°-cos50°=? explain the answer
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sin40°-cos50°= sin40°- cos(90°-50°) [Using identity Cos(90-theta)=sin theta
= sin40°-sin40°=0
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= sin40°-sin40°=0
Here is your answer
HOPE YOU FIND MY ANSWER HELPFUL PLS MARK IT AS THE BRAINLIEST ANSWER IF POSSIBLE
THANK YOU
bhai
and for ur kind information, 98/100 in 12th maths
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