Sin41divided by 2 cos49substracted by 2 sec32 divided by 3 Cosec 58
Answers
Answered by
0
Answer:
Step-by-step explanation:
Sin41/2cos49 - 2sec32/3cosec58
=sin41/2cos(90-41) - 2 sec32-3cosec(90-32)
=sin41/2sin41 - 2sec32/3sec32
=1/2-2/3
=(3-4)/6
=(-1)/6
Answered by
0
[sin41(90-49)]/2cos49-(2sec32(90-58)/3cosec58
[cos49/2cos49]-[2cosec58/ 3cosec58]
1/2-2/3=(3-4)/6=-1/6
[cos49/2cos49]-[2cosec58/ 3cosec58]
1/2-2/3=(3-4)/6=-1/6
Similar questions