Sin42 cos48 +sin48 cos42 ev
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Answered by
2
answer is
sin(A+B)=sinAcosB+cosAsinB
from question,
sin(42+48)=1
sin(A+B)=sinAcosB+cosAsinB
from question,
sin(42+48)=1
Answered by
4
hey...
sin (A+B) = sinA.cosB + sinB.cosA
sin42°.cos48° + sin48°.cos42°
sin(42+48) = sin90° = 1
sin (A+B) = sinA.cosB + sinB.cosA
sin42°.cos48° + sin48°.cos42°
sin(42+48) = sin90° = 1
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