Question

sin42° / sec48° + cos42° / cosec48° -4/3 sin^2 30° = ?

Please solve it. ​

Answer 1

2/3 IS CORRECT ANSWER.....

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Answer 2

$\frac{sin42°}{ sec48°} + \frac{cos42° }{cosec48°} - \frac{4}{3} sin² 30°$

=> $\frac{sin42°}{ sec (90°-42°)} + \frac{cos42° }{cosec(90°-42°)} - \frac{4}{3} sin² 30°$

=> $\frac{sin42°}{ cosec 42°} + \frac{cos42° }{sec 42°} - \frac{4}{3} × \frac{1}{2}$

=> $sin42°+ cos42° - \frac{2}{3}$

=> $1 - \frac{2}{3}$

=> $\frac{3-2}{3}$

=> $\frac{1}{3}$ Ans.

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