Question

sin45° Cos 45°- tan 45​

Answer 1

Answer:

-1/2

Step-by-step explanation:

Hope this answer helped you

Answer 2

Answer:

Step-by-step explanation:

To Find :-

$sin45^{\circ}cos45^{\circ}-tan45^{\circ}$

Solution :-

$sin45^{\circ}=\dfrac{1}{\sqrt{2}}$

$cos45^{\circ}=\dfrac{1}{\sqrt{2}}$

$tan45^{\circ}=1$

Substituting Values :-

$=\dfrac{1}{\sqrt{2}}\times\dfrac{1}{\sqrt{2}}-1$

$=\dfrac{1}{2}-1$

$=\dfrac{1-2}{2}$

$=\dfrac{-1}{2}$

$sin45^{\circ}cos45^{\circ}-tan45^{\circ}=\dfrac{-1}{2}$

Know More :-

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0\end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$