sin45cos30-tan60+sec30=?
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sharvarisonune:
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Heya !!
Sin45° = 1/√2
Cos 30° = √3/2
Tan60° = √3
And,
Sec30° = 2/✓3
Therefore,
Sin 45° × Cos30° - Tan60° + Sec30°
=> 1/✓2 × √3/2 - √3 + 2/✓3
=> √3/2√2 - √3 + 2/√3
=> 3 - 6√2 + 4√2 / 2√6
=> 3 - 2√2/2√6
Sin45° = 1/√2
Cos 30° = √3/2
Tan60° = √3
And,
Sec30° = 2/✓3
Therefore,
Sin 45° × Cos30° - Tan60° + Sec30°
=> 1/✓2 × √3/2 - √3 + 2/✓3
=> √3/2√2 - √3 + 2/√3
=> 3 - 6√2 + 4√2 / 2√6
=> 3 - 2√2/2√6
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