Question

[sin47°/cos43°]² + [cos43°/sin47°]² - 4 cos² 45° = 0​

Answer 1

Step-by-step explanation:

[sin(90-43)/cos43]^2+[cos(90-47)/sin47]^2-4(1/√2)^2=0

[cos43/cos43]^2+[sin47/sin47]^2-2=0

1+1-2=0

0=0

Answer 2

Answer:

find.

$3\%of180$