sin48 × sec 42 + cos 48 × cosec 42 =2
Attachments:
Answers
Answered by
1
sec 42 = cosec(90-42)=cosec48
similarly cosec 42=sec 48
sinA × cosec A=1
cosA *sec A=1
1+1=2hence proved
similarly cosec 42=sec 48
sinA × cosec A=1
cosA *sec A=1
1+1=2hence proved
Anonymous:
follow me for more answers
Answered by
2
sin 48 x sec 42 + cos 48 × cosec 42
sec 42=sec(90-48) cosec(theta)=1/sin(theta)
=cosecc48 sec(theta)=1/cos(theta)
cosec 42=cosec(90-48)
=sec (42)
Sin48 × cosec 42 + cos 48 × sec 42
=>1+1
=>2
sec 42=sec(90-48) cosec(theta)=1/sin(theta)
=cosecc48 sec(theta)=1/cos(theta)
cosec 42=cosec(90-48)
=sec (42)
Sin48 × cosec 42 + cos 48 × sec 42
=>1+1
=>2
Similar questions
Chemistry,
7 months ago
Chemistry,
7 months ago
Computer Science,
1 year ago
English,
1 year ago
Math,
1 year ago