Math, asked by jyothir08082000, 1 year ago

sin480°.cos150°-sin(-150°).cos(-120°)

Answers

Answered by nikolatesla2
1
sin780. sin480 + cos120.sin150 
=sin(8 x 90+60).sin(5 x90+30) + cos(2 x90 -60).sin(2 x90 +30) 
=sin60.cos30 + cos60.(-sin30) 
=sin60.cos30 - cos60.sin30 
=sin(60 -30) 
=sin30 
=1/2
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