Math, asked by samykhaar5urie, 1 year ago

sin4A=4sinAcos*3A-4cosAsin*3

Answers

Answered by ARoy
20
sin4A
=sin(2.2A)
=2sin2Acos2A
=2(2sinAcosA)(cos²A-sin²A)
=4sinAcosA(cos²A-sin²A)
=4sinAcos³A-4cosAsin³A (Proved)
Answered by ArnavVarshney
0

Step-by-step explanation:

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