Question

sin⁴A - cos ⁴A = sin ²A - cos ²A​

Answer 1

Answer:

Refer to the attachment for the solution.

Answer 2

Answer:

Step-by-step explanation:

We know that $x^{2} - y^{2} = (x+y)(x-y)$

now

sin⁴A - cos ⁴A = (sin²A - cos ²A)(sin²A + cos²A)

(sin²A - cos ²A)(sin²A + cos²A)

now it is a trigonometric identity that (sin²A + cos²A) = 1

therefore  the remaining after inserting 1 instead of (sin²A + cos²A) is

(sin²A - cos²A) = RHS

HENCE PROVED

CHEERS MATE, PLEASE MARK BRAINLIEST