Sin4A+Cos4A. = 1/2(2-sin22A)
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Answer:
sin⁴A+cos⁴A
=(sin²A+cos²A)²-2sin²A cos²A
=1-2sin²A cos²A
=1/2(2-4sin²A cos²A)
=1/2{2-(sin2A)²}
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