sin⁴a+cos⁴a/1-2sin²acos²=1
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Step-by-step explanation:
sin^4a +cos^4a first take this
It is written as
(sin^2a + cos^2a)^2 - 2sin^2acos^2a
a^2 + b^2 = (a+b)^2 -2ab
sin^2a + cos ^2a = 1
(sin^2a + cos^2a)^2 - 2sin^2acos^2a = 1 - 2sin^2acos^2a
So,
In the equation
sin⁴a+cos⁴a/1-2sin²acos²=1
Put sin^4a +cos^4a = 1 - 2sin^2acos^2a
1 - 2sin^2acos^2a/1 - 2sin^2acos^2a = 1
Hence Proved
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