Question

sin4A=cos5a,0<A<90,A=​

Answer 1

Answer:

Sin 4A = cos 5A , find A .

Angle A = 90 / (4 + 5) ==> ∠A = 10º

Proof:

sin 4A = sin 40º

sin 40º = cos 50º

cos 5A = cos 50º

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Answer 2

Answer:

ANSWER

sinA−cosA=0

⇒A=cosA

⇒tanA=1

⇒A=

4

π

sin

4

A+cos

4

A=sin

4

4

π

+cos

4

4

π

=(

2

1

)

4

+(

2

1

)

4

=

4

1

+

4

1

=

2

1

.