sin⁴theta+cos⁴theta/1+2sin²theta cos²theta=1
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Answer:
Observe that
sin4θ+cos4θ=1−2sin2θcos2θ⟺sin4θ+cos4θ+2sin2θcos2θ=1
which is always true since
sin4θ+cos4θ+2sin2θcos2θ=(sin2θ+cos2θ)2=12=1
so the identity is proved.
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