sin4theta + sin2theta cos4theta=sin2theta
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taking LHS....
sin2A ( sin2A + cos4A)
sin2A({ sin2A+ (cos2)^2 A}
sin2A( 1 ) {sin2A +cos2A=1}
sin2A
LHS=RHS.
hence proved..
I hope it help you ☺️
sin2A ( sin2A + cos4A)
sin2A({ sin2A+ (cos2)^2 A}
sin2A( 1 ) {sin2A +cos2A=1}
sin2A
LHS=RHS.
hence proved..
I hope it help you ☺️
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