sin4x-cos4x=2sin2x see the question number 10
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KingOMac1:
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lhs=(sinx")"-(cosx")"
=(sinx"-cosx")(sinx"+cosx")
=sinx"-cosx"(1)
=sinx"+sinx"
=sinx"
=rhs
wrong hai
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Answer:
Sin^2x= 1-cos^2x
By LHS
(1-cos^2x)^2 - cos^4x +1
1+cos^4x -2cos^2x +cos^4x +1
2(1-cos^2x)= 2sin^2x
Hence proved
question hi wrong hai
capital C question dekh
buo
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