Question

sin4x-cos4x=sin2x-cos2x​

Answer 1

Answer:

first we have to know the identity then after we have to use the identity

using the identity

Use the identities:

a2−b2=(a−b)(a+b))

cos2x+sin2x=1

sin4x−cos4x=(sin2x−cos2x)

(sin2x+cos2x)

=sin2x−cos2x

hope it helps you ✅✅✅

Answer 2

Step-by-step explanation:

by using:-

$\large{a^2-b^2=(a+b)(a-b)}$

$\large{cos^2 x- sin^2 x= 1}$

$\large{cos^4 x- sin^4 x= (sin^2 x-cos^2 x)(sin^2 x+cos^2 x)}$

$\large{=sin^2 x -cos^2 x}$