Math, asked by kamalsharma42039, 9 months ago

sin4x+sin2x=0 find the general solution

Answers

Answered by doraemonfan

3

Answer:

Sin4x+Sin2x=0

2Sin2x Cos2x + Sin2x=0

Sin2x (2Cos2x+1)=0

Sin2x=0

Sin2x=sin0

2x=0

x=0

2Cos2x + 1=0

Cos2x = -1/2

Cos2x = Cos(π -π/3)

2x = 2π/3

x=π/3

x=0,π/3

Step-by-step explanation:

Hope it helps you

Jai Hind

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