Math, asked by sridharshini7404, 4 months ago

sin4x+sin2x/cos4x+cos2x=tan3x

Answers

Answered by sandy1816

4

Answer:

=sin4x+sin2x/cos4x+cos2x

=2sin(6x/2)cos(2x/2)/2cos(6x/2)cos(2x/2)

=sin3xcosx/cos3xcosx

=sin3x/cos3x

=tan3x

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