Sin5π/12 cos π/12 find the value ???
ksiddharth719:
2+√3 /4
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Hey !!!
Solution :-
=> sin5π/12 . cos π/12
=> sin ( π/2 - π/12 ) .cosπ/12
=> cosπ/12 . cosπ/12
=> cos²π/12
=> cos² 180°/12 = cos²15°
but , cos15° = √3 + 1 / 2√2
since , cos²15°
=> (√3 + 1 / 2√2)²
=> 4 + 2√3 / 8
=> 2 ( 2 + √3 )/ 8
=> 2 + √3/4 Answer ✔
_________________________
Hope it helps you !!!
@Rajukumar111
Solution :-
=> sin5π/12 . cos π/12
=> sin ( π/2 - π/12 ) .cosπ/12
=> cosπ/12 . cosπ/12
=> cos²π/12
=> cos² 180°/12 = cos²15°
but , cos15° = √3 + 1 / 2√2
since , cos²15°
=> (√3 + 1 / 2√2)²
=> 4 + 2√3 / 8
=> 2 ( 2 + √3 )/ 8
=> 2 + √3/4 Answer ✔
_________________________
Hope it helps you !!!
@Rajukumar111
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