Sin55°×cos48°= cos35°×sin42°
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Taking LHS = sin 55 ° cos 48°
We know that
cos θ = sin (90° - θ)
Here, θ = 48°
⇒ sin 55° sin (90° - 48°)
⇒ sin 55° sin 42°
We also know that
Sin θ = cos (90° - θ)
Here, θ = 55°
⇒ cos (90° - 55°) sin 42°
⇒ cos 35° sin 42° = RHS
Hence proved .
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