sin5A -sin3A / cos5A+2cos4A+cos3A=
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Answered by
7
(sin5A-sin3A)/(cos5A+cos3A+2cos4A)
=> 2cos4A.sinA/(2cos4A.cosA+2cos4A)
=> sinA/(1+cosA)
=> sinA (1-cosA)/(1-cos^2A)
=>( 1-cosA)/sinA
=> cosecA-cotA
=> 2cos4A.sinA/(2cos4A.cosA+2cos4A)
=> sinA/(1+cosA)
=> sinA (1-cosA)/(1-cos^2A)
=>( 1-cosA)/sinA
=> cosecA-cotA
BhavanaNali:
sorry
u r wrong
answer is tan A/2
hey dud I am not wrong this is another form of answer you also writ e this in your answer form okay
(1-cosA)/sinA=2sin^2A/2/2sinA/2.cosA /2=tanA/2
don't confuse
Answered by
8
I just want to add points.
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hi
which class r u studying
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