Question

(sin5A-sin3A)/(cos5A+2cos4A+cos3A)​

Answer 1

$\huge\mathbb\color{teal}ANSWER:-$

$\frac{(Sin5A-Sin3A)}{(Cos5A+Cos3A)+2Cos4A}$

$\frac{2Cos4A*SinA}{2Cos4A*CosA+2Cos4A}$

$\frac{2SinA*Cos4A}{2Cos4A(1+CosA)}$

$\frac{SinA}{(1+CosA)}$

$\frac{SinA(1-CosA)}{(1+CosA)(1-CosA)}$

$\frac{SinA(1-CosA)}{1-Cos²A}$

$\frac{SinA(1-CosA)}{Sin²A}$

$\frac{1-CosA}{SinA}$

$\frac{2Sin^2(\frac{A}{2})}{2Sin(\frac{A}{2})Cos(\frac{A}{2})}$

$\frac{Sin(\frac{A}{2})}{Cos(\frac{A}{2})}$

$tan(\frac{A}{2})$