Math, asked by bunug, 1 year ago

sin5x.cos7x find its derivatives

Answers

Answered by iamavinash
7
(sin(5*x)*cos(7*x))'

(sin(5*x))'*cos(7*x)+sin(5*x)*(cos(7*x))'

cos(5*x)*(5*x)'*cos(7*x)+sin(5*x)*(cos(7*x))'

cos(5*x)*((5)'*x+5*(x)')*cos(7*x)+sin(5*x)*(cos(7*x))'

cos(5*x)*(0*x+5*(x)')*cos(7*x)+sin(5*x)*(cos(7*x))'

cos(5*x)*(0*x+5*1)*cos(7*x)+sin(5*x)*(cos(7*x))'

5*cos(5*x)*cos(7*x)+sin(5*x)*(cos(7*x))'

5*cos(5*x)*cos(7*x)+sin(5*x)*-sin(7*x)*(7*x)'

5*cos(5*x)*cos(7*x)+sin(5*x)*-sin(7*x)*((7)'*x+7*(x)')

5*cos(5*x)*cos(7*x)+sin(5*x)*-sin(7*x)*(0*x+7*(x)')

5*cos(5*x)*cos(7*x)+sin(5*x)*-sin(7*x)*(0*x+7*1)

5*cos(5*x)*cos(7*x)+sin(5*x)*7*(-sin(7*x))

5*cos(5*x)*cos(7*x)+sin(5*x)*-7*sin(7*x)

5*cos(5*x)*cos(7*x)-(7*sin(5*x)*sin(7*x))

bunug: please solve it simpleway
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