Question

sin60×cos30+cos60×sin30

Answer 1

$sin \: 6 0 = \sqrt{3} \div 2 \\ cos \: 30 = \sqrt{3} \div 2 \\ cos \: 60 = 1 \div 2 \\ sin \: 30 = 1 \div 2 \\ therefore \: sin \: 60 \times cos \: 30 + cos \: 60 \times sin \: 30 = \sqrt{3} \div 2 \times \sqrt{3} \div 2 + 1 \div 2 \times 1 \div 2 \\ = 3 \div 4 + 1 \div 4 \\ 4 \div 4 \\ = 1$
I hope this helps you

Answer 2

using , complementary angles property ,
sin60 =cos 30 and cos 30= sin60


so required answer is 1