sin60-cos30+cosec 60+tan 30-tan 60
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Heya,
We know that,
sin60° = √3/2
cos30° = √3/2
cosec60° = 2/√3
tan30° = 1/√3
tan60° = √3
Given=> sin60° - cos30° + cosec60° + tan 30° - tan 60°
Putting the value,
=> √3/2 - √3/2 + 2/√3 + 1/√3 - √3
=> 2/√3 + 1√3 - √3
=> (2+1)/√3 -√3
=> 3/√3 - √3
=> √3 - √3
=> 0. ....... Answer
Hope this helps....:)
We know that,
sin60° = √3/2
cos30° = √3/2
cosec60° = 2/√3
tan30° = 1/√3
tan60° = √3
Given=> sin60° - cos30° + cosec60° + tan 30° - tan 60°
Putting the value,
=> √3/2 - √3/2 + 2/√3 + 1/√3 - √3
=> 2/√3 + 1√3 - √3
=> (2+1)/√3 -√3
=> 3/√3 - √3
=> √3 - √3
=> 0. ....... Answer
Hope this helps....:)
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0
I HOPE ITS HELP YOU.
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