Question

sin60 degree cos30degree+sin30degree cos60

Answer 1

#30^o " and " 60^o "are angles of one of the standard triangles"#

#sin(30^o) = 1/2#

#cos(30^o) = sqrt(3)/2#

#sin(60^o) = sqrt(3)/2#

#cos(60^o) = 1/2#

So
#sin(60^o)*cos(30^o) + sin(30^o)*cos(60^o)#

#=(sqrt3/2)(sqrt3/2) +(1/2)(1/2) = 3/4 +1/4#

#=1#

Answer 2

Sin60 cos30 + sin30 cos60
= Sin60 × sin60 + cos60 × cos60
= Sin^2 60 + cos ^2 60
= 1