Question

sin60.tan30+cos60+tan^2 30.tan^2 60.tan45​

Answer 1

Step-by-step explanation:

$\sin(60) \tan(30) + \cos(60) + { \tan }^{2} (30) { \tan }^{2} (60) \tan(45) \\ = \frac{ \sqrt{3} }{2} \times \frac{1}{ \sqrt{3} } + \frac{1}{2} + {( \frac{1}{ \sqrt{3} }) }^{2} \times { (\sqrt{3} )}^{2} \times 1 \\ = \frac{1}{2} + \frac{1}{2} + \frac{1}{3} \times 3 \\ = \frac{1 + 1 + 2}{2} \\ = \frac{4}{2} \\ = 2$