Sin600 cos30+cos120 sin150=k
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Answer:
to evaluate sin 600 cos 30 + cos 120 sin 159
sin 600 = sin (630 - 30 = - cos 30 = -√3/2
cos 30 = √3/2
cos 120 = cos (90 + 30) = - sin 30 = -1/2
sin 150 = sin (180 - 30) = sin 30 = 1/2
by substituting these values, we get
(-√3/2)(√3/2) + (-1/2)(1/2)
=> - 3/4 - 1/4
=> - 1
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