Question

Sin60degrees plus2tan45degrees minus cos30degrees

Answer 1

Answer:

2.

Step-by-step explanation:

$sin60 = \sqrt{3} \div 2 \\ tan45 = 1 \\ cos30 = \sqrt{3} \div 2 \\ \sqrt{3} \div 2 + 2(1) - \sqrt{3} \div 2 \\ = \sqrt{3} \div 2 + 2 - \sqrt{3} \div 2 \\ = take \: lcm \: of \: 2 \\ = \sqrt{3} \div 2 + 4 \div 2 - \sqrt{3} \div 2 \\ = \sqrt{3} + 4 - \sqrt{3} \div 2 \\ = 4 \div 2 \\ = 2 \\ = 2$