sin63degree.cos27degree+cos63degree.sin27degree=1
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Heya user !!
Here's the answer you are looking for
SinA.cosB + cosA.sinB = sin(A + B)
In your question, sin63°.cos27° + cos63.°sin27° ,
it is in the form of SinA.cosB + cosA.sinB
Thus,
sin63°.cos27° + cos63.°sin27°
= sin (63 + 27)°
= sin 90°
= 1 (RHS)
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
SinA.cosB + cosA.sinB = sin(A + B)
In your question, sin63°.cos27° + cos63.°sin27° ,
it is in the form of SinA.cosB + cosA.sinB
Thus,
sin63°.cos27° + cos63.°sin27°
= sin (63 + 27)°
= sin 90°
= 1 (RHS)
★★ HOPE THAT HELPS ☺️ ★★
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