Question

Sin65=a and cos65=b then the value of a²+b²

Answer 1

Answer:

Step-by-step explanation:

Sin65= a

On sq both side

Sin^2 65°=a^2

And, cos65°=b

On sq both side

Cos^2 65=b^2

So,a2+b2= sin ^2 65+ cos^2 65

=> 1 (cos2 theta+sin2 theta = 1)