Question

ம‌‌தி‌ப்பு கா‌ண்க
sin65°〖39〗^'+cos24°57°+tan10°〖10〗^'

Answer 1

Answer:

what we have to prove ?????

Answer 2

விளக்கம்:

$\begin{aligned}&\sin 65^{\circ} 39^{\prime}+\cos 24^{\circ} 57^{\prime}+\tan 10^{\circ} 10^{\prime}\end{aligned}$

$sin& 65^{\circ} 39^{\circ}=>35^{\circ} 39^{\circ}=65^{\circ} 36^{\prime}+3^{\prime}$

$\sin 65^{\circ} 36^{\circ}=0.9107$

பொது வித்தியாசம் $3^{\prime}=4$

$\sin 65^{\circ} 39^{\circ}=0.9111 \ldots \ldots(1)$

$&\cos 24^{\circ} 57^{\prime}=>24^{\circ} 57^{\prime}=24^{\circ} 54^{\prime} +3^{\prime}\end{aligned}$

$24^{\circ} 57^{\prime}=0.9070$

பொது வித்தியாசம் $3^{\prime}=4$

$\begin{array}{l}\cos 24^{\circ} 57^{\circ}=0.966.................(2) \\\tan 10^{\circ} 10^{\circ}=>10^{\circ} 10^{\circ}=10^{\circ} 6^{\prime}+4^{\prime}\end{array}$

$\tan 10^{\circ} 6^{\prime}=>0.1781$

$4^{\prime}=-12(+)$

$\tan 10^{\circ} 10^{\prime}=0.1793 \ldots . .(3)$

சமன்பாடு (1)+(2)+(3) ஐ கூட்ட

$\begin{aligned}&\therefore \sin 65^{\circ} 39^{\prime}+\cos 24^{\circ} 57^{\prime}+\tan 10^{\circ} 10^{\prime}\end{aligned}$

$\begin{array}{l}=0.9111+0.9066+0.1743 \\=1.9970\end{array}$