sin67÷cos33+cos59÷sin31−(tan37×tan53)
Answers
Answered by
0
Answer:
1
Step-by-step explanation:
sin67/cos33+cos59/sin31-(tan37*tan53)
=sin67/cos33+cos59/sin31-(0.75*1.33)
=sin67/cos33+cos59/sin31-1
=0.92/0.84+0.52/0.52-1
=1.1
=1
Answered by
0
Answer:
sin63 =0.92,cos33=0.83
cos59=0.51, sin31=0.51
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sin67÷cos33
0.92÷0.83
1.10.............(1)
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cos59÷sin31
0.51÷0.51
0................(2)
adding equation 1&2
1.10+0=1.10..............(3)
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now
tan37=0.73,tan53=1.32
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0.73×1.32=0.9636...........(4)
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substract equation 4 from equation 3
1.10-0.9636=0.1364
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therefore,the value of the equation is 0.1364
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