Math, asked by knilhari, 11 months ago

sin67÷cos33+cos59÷sin31−(tan37×tan53)​

Answers

Answered by Tendon
0

Answer:

1

Step-by-step explanation:

sin67/cos33+cos59/sin31-(tan37*tan53)

=sin67/cos33+cos59/sin31-(0.75*1.33)

=sin67/cos33+cos59/sin31-1

=0.92/0.84+0.52/0.52-1

=1.1

=1

Answered by nmsawant13
0

Answer:

sin63 =0.92,cos33=0.83

cos59=0.51, sin31=0.51

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sin67÷cos33

0.92÷0.83

1.10.............(1)

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cos59÷sin31

0.51÷0.51

0................(2)

adding equation 1&2

1.10+0=1.10..............(3)

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now

tan37=0.73,tan53=1.32

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0.73×1.32=0.9636...........(4)

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substract equation 4 from equation 3

1.10-0.9636=0.1364

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therefore,the value of the equation is 0.1364

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