sin690cos930+tan(-765)cosec9-1170)
Answers
Answered by
0
Step-by-step explanation:
sin690°cos930°+tan(−765°)csc(−1170°)
=sin(720−30)cos(900+30)+tan(−720+45)csc(3×360+90)
=(−sin30°)(−cos30°)+tan(45°)csc(90°)
=(−
2
1
)(−
2
3
)+(1)(1)
=1+
4
3
=
4
3
+4
.
Answered by
1
Answer:
Step-by-step explanation:
Sin690cos930+tan(-765)cosec(-1170).
=Sin(630+60)cos(900+30) + Tan(720+45)cosec(1170+0). [tan(-x)= -tan x & cosec(-x)= -cosec x].
= (-Cos 60)(-cos 30)+tan 45 sec 0.
= (-1/2)(-√3/2) + (1 )(1).
=√3/4+ 1.
=(√3+4)/4.
Hope it helps.
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