sin690cos930+tan-765cosec-1170
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Answered by
45
Sin690cos930+tan(-765)cosec(-1170).
=Sin(630+60)cos(900+30) + Tan(720+45)cosec(1170+0). [tan(-x)= -tan x & cosec(-x)= -cosec x].
= (-Cos 60)(-cos 30)+tan 45 sec 0.
= (-1/2)(-√3/2) + (1 )(1).
=√3/4+ 1.
=(√3+4)/4.
Hope it helps.
=Sin(630+60)cos(900+30) + Tan(720+45)cosec(1170+0). [tan(-x)= -tan x & cosec(-x)= -cosec x].
= (-Cos 60)(-cos 30)+tan 45 sec 0.
= (-1/2)(-√3/2) + (1 )(1).
=√3/4+ 1.
=(√3+4)/4.
Hope it helps.
Answered by
16
Answer: sin(720-30)°cos(900+30)°-tan(720+45)°cosec(-1170+0)°
Sin(4π-30°)cos(5π+30°)-tan(4π+45°)-cosec(-1170+0°)
(-cos60°)(-cos30°)+tan45°sec0°
(-1/2)-(√3/2)+1*1
√3/4+1
√3+4/4
Step-by-step explanation:
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