Sin⁶A+Cos⁶A = 1-3Sin²A
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Answered by
1
Answer:
sin^6A + cos^6A
= (sin^2A)3 + (cos^2A)3
= (sin^2A + cos^2A)(sin^4A – sin^2Acos^2A + cos^4A)
= 1 (sin^4A – sin^2Acos^2A + cos^4A + 2sin^2Acos^2A – 2sin^2Acos^2A)
= (sin2A + cos2A) – 3sin2Acos2A
= 1 – 3sin^2Acos^2A
Answered by
2
Answer:
sorry bro , I forget the math's term ,
because technometry has been cut off from my book syllabus .
I can do to figure it out, a few months ago .
it was my favorite chapter. but now I forget out.
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