Math, asked by swaroopskaimal, 1 year ago

Sin6A +cos6A +3sin2Acos2A = 1

Answers

Answered by Nitin2112
8

(sin^2A)^3 + (cos^2A)^3 + 3(sin^2A)(cos^2A)(sin^2A + cos^2A)=1

=(sin^2A+cos^2A)^3=1

=1^3=1

=1=1

LHS=RHS

Plz mark it as brainliest


swaroopskaimal: Ty
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