sin6teta+cos6teta=1-3sin2teta. cos2cos2teta
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hope this is the answer u want....
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Anonymous:
plz mark as brainliest....
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just evaluate the equation and use this:
!) sin^2theta+cos^2theta=1
2)identity of a^3+b^3
!) sin^2theta+cos^2theta=1
2)identity of a^3+b^3
the answer will be 1-3 sin^2theta
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