Question

sin6thita=? what is the value?

Answer 1

$here \: i \: will \: take \: \alpha \: in \: place \: of \: theeta \\ \\ \sin(6 \alpha ) = \sin(3(2 \alpha )) \\ use \: formula \: of \: \sin(3x) = (3 \sin(x) - 4 {sin}^{3} x) \\ \\ = \sin( 6\alpha ) = (3 \sin(2 \alpha ) - 4 { \sin}^{3} 2 \alpha ) \\ now \: put \: value \: of \: \sin( 2\alpha ) = 2 \sin( \alpha ) . \cos( \alpha ) \\ and \: get \: ur \: answer.$