Math, asked by priyanka3947, 6 months ago

sin⁶x+cos⁶x = 1-3sin²xcos²x

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Answered by Anonymous

3

Answer:

It can be written as (cos²x) ³+(sin²x)³=(cos²x+sin²x)(cos⁴x+sin⁴x-sin²xcos²x)As we know that (a³+b³) =(a+b) (a²+b²-ab) Now cos⁴x+sin⁴x .

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